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-8x^2+64x-60=68
We move all terms to the left:
-8x^2+64x-60-(68)=0
We add all the numbers together, and all the variables
-8x^2+64x-128=0
a = -8; b = 64; c = -128;
Δ = b2-4ac
Δ = 642-4·(-8)·(-128)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-64}{-16}=+4$
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